Unicode Han Character 'sugar cane' (U+27039)

previous character next character

𧀹
U+27039 browser display

sugar cane

image of Unicode Han Character 'sugar cane' (U+27039)
Raster image of U+27039

sugar cane

Unicode Data
Name sugar cane
Block CJK Unified Ideographs Extension B
Category Letter, Other [Lo]
Script Han (Hani)
Combine 0
BIDI Left-to-Right [L]
Version Unicode 3.1.0 (March, 2001)
Unicode Han Data
kIRG_GSource GKX-1066.04
kIRGKangXi 1066.040
kSemanticVariant U+8517<kFennIndex:T
kIRG_USource UTC-00447
kKangXi 1066.040
kIRG_TSource T7-493C
kJapanese シャ
kMojiJoho MJ047141 MJ047142:E0100 MJ047141:E0101
kRSUnicode 140.15
kFenn 201G
kDefinition sugar cane
kMorohashi 32345:E0100
kFennIndex 21.13
kIRG_JSource JMJ-047141
kCantonese ze3
kIRGHanyuDaZidian 53321.120
kHanYu 53321.120
kMandarin zhè
kTotalStrokes 19
Encodings
HTML Entity (decimal) &#159801;
HTML Entity (hex) &#x27039;
How to type in Microsoft Windows Alt +27039
UTF-8 (hex) 0xF0 0xA7 0x80 0xB9 (f0a780b9)
UTF-8 (binary) 11110000:10100111:10000000:10111001
UTF-16 (hex) 0xD85C 0xDC39 (d85cdc39)
UTF-16 (decimal) 55,388 56,377
UTF-32 (hex) 0x00027039 (27039)
UTF-32 (decimal) 159,801
C/C++/Java source code "\uD85C\uDC39"
Python source code u"\U00027039"
More...
Java Data
string.toUpperCase() 𧀹
string.toLowerCase() 𧀹
Character.UnicodeBlock CJK_UNIFIED_IDEOGRAPHS_EXTENSION_B
Character.charCount() 2
Character.getDirectionality() DIRECTIONALITY_LEFT_TO_RIGHT [0]
Character.getNumericValue() -1
Character.getType() 5
Character.isDefined() Yes
Character.isDigit() No
Character.isIdentifierIgnorable() No
Character.isISOControl() No
Character.isJavaIdentifierPart() Yes
Character.isJavaIdentifierStart() Yes
Character.isLetter() Yes
Character.isLetterOrDigit() Yes
Character.isLowerCase() No
Character.isMirrored() No
Character.isSpaceChar() No
Character.isSupplementaryCodePoint() Yes
Character.isTitleCase() No
Character.isUnicodeIdentifierPart() Yes
Character.isUnicodeIdentifierStart() Yes
Character.isUpperCase() No
Character.isValidCodePoint() Yes
Character.isWhitespace() No