Unicode Han Character 'the linch-pin of a wheel to govern or control the noise of a barrow' (U+2CB6A)

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𬭪
U+2CB6A browser display

the linch-pin of a wheel to govern or control the noise of a barrow

image of Unicode Han Character 'the linch-pin of a wheel to govern or control the noise of a barrow' (U+2CB6A)
Raster image of U+2CB6A

the linch-pin of a wheel to govern or control the noise of a barrow

Unicode Data
Name the linch-pin of a wheel to govern or control the noise of a barrow
Block CJK Unified Ideographs Extension E
Category Letter, Other [Lo]
Script Han (Hani)
Combine 0
BIDI Left-to-Right [L]
Version Unicode 8.0 (June 2015)
Unicode Han Data
kIRG_GSource GGH-2021.45
kPhonetic 491*
kCantonese hat6
kTraditionalVariant U+938B
kRSUnicode 167'.10
kMandarin xiá
kTotalStrokes 15
kDefinition the linch-pin of a wheel to govern or control the noise of a barrow
Encodings
HTML Entity (decimal) 𬭪
HTML Entity (hex) 𬭪
How to type in Microsoft Windows Alt +2CB6A
UTF-8 (hex) 0xF0 0xAC 0xAD 0xAA (f0acadaa)
UTF-8 (binary) 11110000:10101100:10101101:10101010
UTF-16 (hex) 0xD872 0xDF6A (d872df6a)
UTF-16 (decimal) 55,410 57,194
UTF-32 (hex) 0x0002CB6A (2cb6a)
UTF-32 (decimal) 183,146
C/C++/Java source code "\uD872\uDF6A"
Python source code u"\U0002CB6A"
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Java Data
string.toUpperCase() 𬭪
string.toLowerCase() 𬭪
Character.UnicodeBlock CJK_UNIFIED_IDEOGRAPHS_EXTENSION_E
Character.charCount() 2
Character.getDirectionality() DIRECTIONALITY_LEFT_TO_RIGHT [0]
Character.getNumericValue() -1
Character.getType() 5
Character.isDefined() Yes
Character.isDigit() No
Character.isIdentifierIgnorable() No
Character.isISOControl() No
Character.isJavaIdentifierPart() Yes
Character.isJavaIdentifierStart() Yes
Character.isLetter() Yes
Character.isLetterOrDigit() Yes
Character.isLowerCase() No
Character.isMirrored() No
Character.isSpaceChar() No
Character.isSupplementaryCodePoint() Yes
Character.isTitleCase() No
Character.isUnicodeIdentifierPart() Yes
Character.isUnicodeIdentifierStart() Yes
Character.isUpperCase() No
Character.isValidCodePoint() Yes
Character.isWhitespace() No