Unicode Han Character '(same as 業) in ancient China, big piece of board (plank) on a music rack with the carving of the shape of saw's teeth; used to hang clock (musical stone, drum, etc.), instruction' (U+3E23)

Unicode Han Character '(same as 業) in ancient China, big piece of board (plank) on a music rack with the carving of the shape of saw's teeth; used to hang clock (musical stone, drum, etc.), instruction' (U+3E23)

previous character next character

Unicode Han Data
kIRG_GSource GKX-0694.28
kIRGKangXi 0694.280
kSBGY 545.13
kCangjie LLTCD
kKPS1 56C3
kIRG_KSource K3-2A54
kIRG_TSource T7-392D
kRSUnicode 91.13
kDefinition (same as 業) in ancient China, big piece of board (plank) on a music rack with the carving of the shape of saw's teeth; used to hang clock (musical stone, drum, etc.), instruction
kCantonese zip6
kIRGHanyuDaZidian 32020.170
kHanyuPinyin 32020.170:yè
kHanYu 32020.170
kIRG_KPSource KP1-56C3
kMandarin
kTotalStrokes 17
Encodings
HTML Entity (decimal) 㸣
HTML Entity (hex) 㸣
How to type in Microsoft Windows Alt +3E23
UTF-8 (hex) 0xE3 0xB8 0xA3 (e3b8a3)
UTF-8 (binary) 11100011:10111000:10100011
UTF-16 (hex) 0x3E23 (3e23)
UTF-16 (decimal) 15,907
UTF-32 (hex) 0x00003E23 (3e23)
UTF-32 (decimal) 15,907
C/C++/Java source code "\u3E23"
Python source code u"\u3E23"
More...
Java Data
string.toUpperCase()
string.toLowerCase()
Character.UnicodeBlock CJK_UNIFIED_IDEOGRAPHS_EXTENSION_A
Character.charCount() 1
Character.getDirectionality() DIRECTIONALITY_LEFT_TO_RIGHT [0]
Character.getNumericValue() -1
Character.getType() 5
Character.isDefined() Yes
Character.isDigit() No
Character.isIdentifierIgnorable() No
Character.isISOControl() No
Character.isJavaIdentifierPart() Yes
Character.isJavaIdentifierStart() Yes
Character.isLetter() Yes
Character.isLetterOrDigit() Yes
Character.isLowerCase() No
Character.isMirrored() No
Character.isSpaceChar() No
Character.isSupplementaryCodePoint() No
Character.isTitleCase() No
Character.isUnicodeIdentifierPart() Yes
Character.isUnicodeIdentifierStart() Yes
Character.isUpperCase() No
Character.isValidCodePoint() Yes
Character.isWhitespace() No