Unicode Han Character 'acorn cup' (U+6882)

Unicode Han Character 'acorn cup' (U+6882)

previous character next character

Unicode Han Data
kCNS1986 1-5B42
kMeyerWempe 1086e
kJapaneseOn KYUU GU KYOKU KOKU
kIRGKangXi 0528.040
kCangjie DIJE
kKPS1 4B8A
kRSKangXi 75.7
kIRG_HSource HB1-B1FC
kIRG_KSource K2-3A78
kIRG_TSource T1-5B42
kIRG_VSource V0-397D
kJapaneseKun NOMINOSAKI
kBigFive B1FC
kRSAdobe_Japan1_6 C+17801+75.4.7
kHanYu 21210.080
kCNS1992 1-5B42
kGB3 3350
kCCCII 223C76
kMandarin qiú
kTotalStrokes 11
kIRG_GSource G3-4152
kEACC 223C76
kSBGY 210.32
kJIS0213 2,14,74
kKangXi 0528.040
kIRGDaeJaweon 0916.190
kRSUnicode 75.7
kJis1 3575
kDefinition acorn cup
kMorohashi 14826
kCihaiT 698.501
kIRG_JSource J14-2E6A
kCantonese kau4
kVietnamese cầu
kIRGDaiKanwaZiten 14826
kIRGHanyuDaZidian 21210.080
kFourCornerCode 4393.2
kIICore AT
kHanyuPinyin 21210.080:qiú
kIRG_KPSource KP1-4B8A
kDaeJaweon 0916.190
Encodings
HTML Entity (decimal) 梂
HTML Entity (hex) 梂
How to type in Microsoft Windows Alt +6882
UTF-8 (hex) 0xE6 0xA2 0x82 (e6a282)
UTF-8 (binary) 11100110:10100010:10000010
UTF-16 (hex) 0x6882 (6882)
UTF-16 (decimal) 26,754
UTF-32 (hex) 0x00006882 (6882)
UTF-32 (decimal) 26,754
C/C++/Java source code "\u6882"
Python source code u"\u6882"
More...
Java Data
string.toUpperCase()
string.toLowerCase()
Character.UnicodeBlock CJK_UNIFIED_IDEOGRAPHS
Character.charCount() 1
Character.getDirectionality() DIRECTIONALITY_LEFT_TO_RIGHT [0]
Character.getNumericValue() -1
Character.getType() 5
Character.isDefined() Yes
Character.isDigit() No
Character.isIdentifierIgnorable() No
Character.isISOControl() No
Character.isJavaIdentifierPart() Yes
Character.isJavaIdentifierStart() Yes
Character.isLetter() Yes
Character.isLetterOrDigit() Yes
Character.isLowerCase() No
Character.isMirrored() No
Character.isSpaceChar() No
Character.isSupplementaryCodePoint() No
Character.isTitleCase() No
Character.isUnicodeIdentifierPart() Yes
Character.isUnicodeIdentifierStart() Yes
Character.isUpperCase() No
Character.isValidCodePoint() Yes
Character.isWhitespace() No